Two trains are traveling from point A to point B such that the speed of first train is 65 kmps and the speed of 2 train is 29 kmph. Where is the distance b/w A&B such that the slower train reached 5 hrs late compared to the faster?

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xiang su Profile
xiang su answered
We can learn from that : 65×t1=distance ;
29×t2=distance;
and ,t2=t1+5 hours =t1+5×3600s ;
t1=14500s
and then : Distance = 65×14500 kilometers=942500 kilometers.

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