Someone in a car going past you at the speed of 41 m/s drops a small rock from a height of 1.8 m. How far from the point of the drop will the rock hit the ground? The acceleration due to gravity is 9.8 m/s2. Answer in units of m.


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Kr Ashwin Profile
Kr Ashwin , Data Entry, answered

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Atul Chhotray Profile
Atul Chhotray answered
WE can divide the problem into two parts one involving horizontal motion of the object and the other involving vertical motion.  Analysis of vertical Motion will provide us with the travel time i.e. How long the rock will take to hit the ground. Using the Second eq of motion  s = ut + 1/2 a t*t => you = 0 (no velocity in downwards direction)So, t*t = 2s/g = 3.6/9.8t = 0.606  Horizontal Motion: Since no acceleration is involved in the horizontal direction, so distance covered = you*t = 41 * 0.606 = 24.846m

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