If An Engine Must Do 500 Joules Of Work To Pull A 10kg Load Up To A Height Of 4 Meters, What Is The Efficiency Of The Engine?


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The work done in displacing a load of mass m against the gravitation g through a height h is given by
w=mgh. Here the mass or load m= 10kg , g=9.81m/sec^2(assumed) and h = 4 metres.Threfore ,
w = (10g)(9.81m/s^2)(4m) =392.4 NM =392 joules
Therfore, the engine worked 500 joules, which resulted in a rsult of 392.4J
Therfore, the Effiency of the engine = (Resulted work/Actual work)*100

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